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Factoring
July 18th, 2010 06:21 PM
Category : College / University - Mathematics
ChristianT20

factor completely: f(x)=2x^5+3x^4+47x^3+73x^2-75x-50

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joyride
Answers by ( joyride ) : 138
factoring

Hi Christian,

Welcome to PlentyofTutors!

This one is a real pain, there is no easy way to factor a power of 5.

step 1.  Guess one solution:  Try to find a number for x that makes the function zero.  You can either literally keep plugging in numbers to find a solution, or if you have a computer, plug it into an excel file and find solutions.  I used excel, with random numbers for x, and you can easily see from the attached excel file, that there are two solutions, x = 1, -2

step 2.  Once you know a solution, you also know a factor.  For example, because we know the solutions are x = 1 and x = -2, then we know that two factors are (x-1) and (x+2).

step 3.  what you can do know is take one factor, like (x-1), and divide the whole polynomial by that factor.

step4.   take the resulting answer from step 3, and divide that polynomial by the second factor (x+2).

I have divided them out for you in the attached pdf.  It is messy, I'm sorry.  If you can't follow it, just let me know and I will clarify.

Have a good one!

 

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factorpower5.xls
factorpow5.pdf
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